Use sibling recursion:
<xsl:template match="a" mode="new-group">
<group>
<xsl:apply-templates select="following-sibling::a[1][. = current()+1]"
mode="same-group"/>
</group>
<xsl:apply-templates select="following-sibling::a[not(. =
preceding-sibling::a+1)][1]" mode="new-group"/>
</xsl:template>
<xsl:template match="a" mode="same-group">
<xsl:apply-templates select="following-sibling::a[1][. = current()+1]"
mode="same-group"/>
</xsl:template>
<xsl:template match="*[a]">
<xsl:apply-templates select="child::a[1]" mode="new-group"/>
</xsl:template>
Not tested.
Michael Kay
Saxonica
On 24 Mar 2014, at 14:08, Mario Madunic
<mario(_dot_)madunic(_at_)aeroinfo(_dot_)com> wrote:
(using XSLT 1)
Hi,
I would like to group numbers by if the following number is current number +
1 and so on.
Example:
<a>1</a>
<a>3</a>
<a>4</a>
<a>5</a>
<a>7</a>
<a>9</a>
<a>10</a>
<group><a>1</a></group>
<group><a>3 <a>4</a> <a>5</a></group>
<group><a>7</a></group>
<group><a>9</a> <a>10</a></group>
Any insight will be appreciated.
Thanks
Mario Madunic | Software Developer | AeroInfo Systems, A Boeing Company |
mario(_dot_)madunic(_at_)aeroinfo(_dot_)com | #200-13575 Commerce Parkway |
Richmond, BC, V6V 2L1, Canada | www.aeroinfo.com | www.boeing.com
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