On Sat, Mar 29, 2014 at 4:13 PM, Abel Braaksma (Exselt)
<abel(_at_)exselt(_dot_)net> wrote:
I don't think you can do everything
with XSLT 1.0 that you can do now with a subset that does not include
xsl:if (xsl:choose can be implemented in xsl:ifs).
If I understand this correctly, it says that <xsl:choose> cannot be
implemented if there is no <xsl:if> instruction available.
But it can.
An <xsl:choose> with N outcomes can be expressed in XSLT 2 as a single:
<xsl:apply-templates select="my:special-node"/>
and N templates of the form:
<xsl:template match="my:special-node[condition]">
<!-- The wanted code here -->
<xsl:template>
In XSLT 1.0 we sometimes can only specify the condition within a
predicate in the "select" attribute of the <xsl:apply-templates>
instruction.
Thus, an <xsl:choose> with N outcomes can be implemented using N
<xsl:apply-templates> instructions of the form:
<xsl:apply-templates select="my:special-node[conditionK]"/>
and N templates -- exactly as in the case for XSLT 2.0 above.
This is the full proof that XSLT conditional instructions can be
eliminated in any version of XSLT.
BTW, I have quite a lot of experience writing complex transformations
without any XSLT conditional instructions. :)
Cheers,
Dimitre Novatchev
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