A most timely thread for me. I just encountered the "simplified stylesheet."
I ran into it in the first design-pattern example of Chapter 17, "Stylesheet
Design Patterns," in Michael's "XSLT2.0 and XP2ath 2.0, 4th ed." (BTW, when
can we expect the XSLT 3.0 book?]
The stylesheet there starts with
<html xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xsl:version="2.0">
and has no xsl:stylsheet element. It was strange to see instances of XSLT
elements xsl:for-each and xsl: value-of in that stylesheet without the
xs:stylesheet element as the outermost element. I since learned that as long
as the XSLT namespace is declared and there is an xsl:version attribute in its
outermost element, which can't be in the XSLT namespace, it's an XSLT
stylesheet!
Thus the following also counts as an XSLT stylesheet:
<html xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xsl:version="2.0"/>
--Jack Kulas
LSI, Inc
Jacksonvlle, FL
-----Original Message-----
From: Michael Kay [mailto:mike(_at_)saxonica(_dot_)com]
and that works perfectly well. But then I tried the slightly simpler
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0"/>
Yes, that's a legal stylesheet.
But Saxon-HE 9.5.1.3J run from the commandline complains that "The
supplied file does not appear to be a stylesheet"
(this is an error, not a warning; # XTSE0150).
I suspect you got the command line arguments wrong. This message from Saxon
means that the file supplied as the stylesheet document did not have
xsl:stylesheet or xsl:transform as its root. In fact more specifically I think
it means the local name of the root element was not "stylesheet" or "transform"
- you get a different message if only the namespace is wrong.
Michael Kay
Saxonica
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