Max,
What happens when you do this?
<xsl:element name="a" type="xs:integer">
<xsl:sequence select="5"/>
</xsl:element>
or even select="xs:integer(5)" ...?
I suppose I could always try. :->
Cheers, Wendell
On Wed, Jun 11, 2014 at 11:45 AM, Max Toro maxtoroq(_at_)gmail(_dot_)com
<xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:
The following doesn't work in an XSLT processor with basic conformance:
<xsl:element name="a" type="xs:integer">5</xsl:element>
even though you can create variables using the built-in types:
<xsl:variable name="a" select="5" as="xs:integer"/>
or use the constructor functions:
<xsl:variable name="a" select="xs:integer('5')"/>
What's the reason for this restriction? Why can't I use built-in types
to annotate new nodes?
--
Max Toro
--
Wendell Piez | http://www.wendellpiez.com
XML | XSLT | electronic publishing
Eat Your Vegetables
_____oo_________o_o___ooooo____ooooooo_^
--~----------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
EasyUnsubscribe: http://lists.mulberrytech.com/unsub/xsl-list/1167547
or by email: xsl-list-unsub(_at_)lists(_dot_)mulberrytech(_dot_)com
--~--