Re: [xsl] Pattern notation for preceding-sibling

Heiko Niemann kontakt(_at_)heiko-niemann(_dot_)de wrote:

> Elements A,B,B,N,E,B,C are contained in element foo.
> Now I want A,N to be returned, so my first guess is, that this might work:
>
> /foo/E/preceding-sibling::(A,N)
>
> But it does not, so I either have to write
>
> /foo/E/(preceding-sibling::A, preceding-sibling::N) or
> So, is there a (short) notation that I missed so far, that does what I
> expected /foo/E/preceding-sibling::(A,N) to do?
No, I don't think so.
--~----------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
EasyUnsubscribe: http://lists.mulberrytech.com/unsub/xsl-list/1167547
or by email: xsl-list-unsub(_at_)lists(_dot_)mulberrytech(_dot_)com
--~--