Re: [xsl] Creating new, distinct groups of ranges from an aggregation of

On Tue, Nov 18, 2014 at 05:06:55AM -0000, Michael Friedman
sumarimike(_at_)hotmail(_dot_)com scripsit:
> Greetings, I'm trying to use XSLT 2.0 to create a new set of grouped
> ranges based on the overlap of an aggregation of a set of
> non-contiguous individual ranges. Example: Given a range of numbers as
> an individual set:1. <range>150-202</range>2. <range>201-225</range>3.
> <range>201-204</range>4. <range>205-234</range>5. <range>226-234,
> 250-260</range>
[snip]
> I've been using <xsl:sequence> to find all the numbers of a single
> range, so I can do compares against individual numbers in the entire
> range, if necessary. But, it seems like it may be easier to just work
> with the boundaries: the start and end points and see if a value falls
> within it, somehow, rather than iterating repetitively through
> enumerations of sequences.
Well, you could -- since this is a copy being processed toward XSL-FO,
not canonical archival content -- start splitting things inside the
range elements:

<range>
    <xsl:for-each select="tokenize(string(.),',')">
        <start><xsl:value-of select="tokenize(.,'-')[1]"/></start>
        <end><xsl:value-of select="tokenize(.,'-')[last()]"/></end>
    </xsl:for-each>
</range>

> From there you -- if I'm understanding the use case, and it's late here,
so I could well not -- could presumably use sequences of range/start and
range/end values, sort it, and consume it from the front, to create the
aggregated ranges.

So, if the altered range elements are in $split,

<xsl:variable name="pairs">
    <xsl:perform-sort select="$split/range/start | $split/range/end" >
        <xsl:sort select="."/>
    </xsl:perform-sort>
</xsl:variable>

and then you can consume $pairs pair-wise from the front, using
subsequence(), to get that actual ranges.

(XSLT has not been tested.)

Did that make any sense at all?

-- Graydon
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