Re: [xsl] processing nodes by value precedence

On 2 February 2016 at 20:57, Matthew Stoeffler 
matthew(_dot_)stoeffler(_at_)ithaka(_dot_)org
<xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:

> Lets say I’m processing products that can have multiple types of a certain
> node distinguished by value, of which I want only one in my result, and I
> have a precedence order by type of those nodes that shoudl determine which
> one I get.  So, if the child of product I’m interested in is price currency
> and my product had
>
>
>
> <product>
>
> ….
>
>
>
> <price>
>
> <amount>25.00</amount>
>
> <currency>FR</currency>
>
> </price>
>
>
>
> <price>
>
> <amount>20.00</amount>
>
> <currency>US</currency>
>
> </price>
>
>
>
> <price>
>
> <amount>30.00</amount>
>
> <currency>CA</currency>
>
> </price>
>
>
>
> </product>
>
>
>
> And my preference is to take the only one price in the order 1., US, 2.
> CA, 3.FR.
>
>
>
> In context product, if I say
>
>
>
> <xsl:apply-templates
> select=“(price[currency=‘US’],price[currency=‘CA’],price[currency=‘FR’])[1]”/>
>
>
>
> I get the FR price because it’s first in doc order, but my expression was
> meant to say process nodes in this sequence order, taking the first one, in
> the sequence, not in the doc order of the input tree.
>
> No you should get the US one. if you execute
<xsl:stylesheet version="2.0" xmlns:xsl="
http://www.w3.org/1999/XSL/Transform";>

 <xsl:template match="product">
  <xsl:copy-of
select="(price[currency='US'],price[currency='CA'],price[currency='FR'])[1]"/>
 </xsl:template>
</xsl:stylesheet>


on the xml you posted then you get

<price>

<amount>20.00</amount>

<currency>US</currency>

</price>


Does you real code have a path step  /xxx after the comma expression? (that
would sort into document order)

David


> I thought the above instruction would be a short cut to achieving this,
> but it doesn’t work. Is there a concise way to express  the kind of
> precedence I want?
>
>
>
> Thanks.

-- 
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