Re: [xsl] Need an XPath expression which checks that all commas are esca

Martin wrote:

Shouldn't the check rather be
   every $token in tokenize(., ',')[position() lt last()] satisfies 
ends-with($token, '\') 

Ah!

You are right!

Thanks Martin.

/Roger

-----Original Message-----
From: Martin Honnen martin(_dot_)honnen(_at_)gmx(_dot_)de 
[mailto:xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com] 
Sent: Friday, November 3, 2017 2:09 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Need an XPath expression which checks that all commas are 
escaped

On 03.11.2017 19:03, Costello, Roger L. costello(_at_)mitre(_dot_)org wrote:

> I need an XPath 2.0 expression for this:
>
>       Check that each comma in the <value>
>       element is escaped with a backslash.
Do you want that expression to return a boolean value of true or false?

> Examples:
>
> This is good:
>
> <value>A\, B</value>
>
> This is bad:
>
> <value>A, B</value>
>
> This is also bad, because one comma is escaped but the other is not:
>
> <value>A\, B, C</value>
>
> I created an XPath expression to see if the text is good:
>
> tokenize(text(), ',')[position() lt last()][ends-with(., '\')]
>
> I think that is correct. Is there a simpler XPath expression to solve this?
Shouldn't the check rather be
   every $token in tokenize(., ',')[position() lt last()] satisfies 
ends-with($token, '\') ?

--~----------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
EasyUnsubscribe: http://lists.mulberrytech.com/unsub/xsl-list/1167547
or by email: xsl-list-unsub(_at_)lists(_dot_)mulberrytech(_dot_)com
--~--