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Re: [xsl] for-each-group

2018-03-28 11:06:04
Try group-adjacent="concat(local-name(), if (self::figure) then position() else 
0))"

which will work for your example though it may not match your general intent...

Michael Kay
Saxonica


On 28 Mar 2018, at 16:53, Rick Quatro rick(_at_)rickquatro(_dot_)com 
<xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:

Hi All,
 
I have a <step> element that looks something like this:
 
<steps>
  <step>
    <para>Intro stuff</para>
    <para>More intro stuff</para>
    <figure/>
    <figure/>
    <para>Conclusion stuff</para>
    <para>More conclusion stuff</para>
  </step>
</steps>
 
I want 4 separate groups:
 
1) First two <para> elements.
2) First <figure>
3) Second <figure>
4) Last two <para> elements.
 
Here is my stylesheet:
 
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform 
<http://www.w3.org/1999/XSL/Transform>"
    xmlns:xs="http://www.w3.org/2001/XMLSchema 
<http://www.w3.org/2001/XMLSchema>"
    exclude-result-prefixes="xs"
    version="2.0">
    
    <xsl:template match="/steps">
        <xsl:apply-templates select="step"/>
    </xsl:template>
    
    <xsl:template match="step">
        <xsl:for-each-group select="*" group-starting-with="figure">
            <xsl:message select="count(current-group())"></xsl:message>
        </xsl:for-each-group>
    </xsl:template>
    
</xsl:stylesheet>
 
I get the first two groups, but the last two <para> elements are part of the 
last <figure>'s group instead of being separate.
 
I tried using group-by="figure" but I don't get any output. Any help would be 
appreciated. Thank you very much.
 
Rick
 
Rick Quatro
Carmen Publishing Inc.
rick(_at_)frameexpert(_dot_)com <mailto:rick(_at_)frameexpert(_dot_)com>
FrameMaker toys: www.frameexpert.com/store <http://www.frameexpert.com/store>
585-366-4017
 
 
 
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