Re: [xsl] for-each-group

On 28.03.2018 18:22, Rick Quatro rick(_at_)rickquatro(_dot_)com wrote:
> OK, I think I get it. You are grouping on a string derived from the node 
> name instead of the node itself. This doesn't work for my general 
> intent, because the other elements may not all be the same. For example, 
> I might have this:
> <steps>
>
>    <step>
>
>      <para>Intro stuff</para>
>
>      <para>More intro stuff</para>
>
>      <figure/>
>
>      <figure/>
>
>      <para>Conclusion stuff</para>
>
>      <table>More conclusion stuff</table>
>
>      <para>More conclusion stuff</para>
>
>    </step>
>
> </steps>
>
> and I would want the three elements following the last figure to be in a 
> single group.
  <xsl:template match="step">
      <xsl:copy>
          <xsl:for-each-group select="*" group-adjacent="if 
(not(boolean(self::figure))) then true() else (position() - 1 idiv 1)">
              <group>
                  <xsl:apply-templates select="current-group()"/>
              </group>
          </xsl:for-each-group>
      </xsl:copy>
  </xsl:template>

might do
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