[xsl] XPath to find duplicate elements

Hello

I have an xml file where I need and XPath expression to find all elements that 
are a copy of a previous element in the same file. 

I came up with the following:


let $xml := <a>
                <b>
                    <c>1</c>
                    <d>1</d>
                    <d>2</d>
                </b>
                <b>
                    <c>2</c>
                    <d>1</d>
                    <d>3</d>
                </b>
                <b>
                    <c>3</c>
                    <d>2</d>
                    <d>3</d>
                </b>
                <b>
                    <c>3</c>
                    <d>2</d>
                    <d>3</d>
                </b>
            </a>
            return
            
$xml//*[let $node1 := . return some $node2 in $xml//*[. << $node1] satisfies 
deep-equal($node1,$node2)]/(ancestor-or-self::node()/concat(node-name(.),1+count(preceding-sibling::*)),'&#10;')

which gives 

 a1 b2 d2 
 a1 b3 d2 
 a1 b3 d3 
 a1 b4 
 a1 b4 c1 
 a1 b4 d2 
 a1 b4 d3 


This is actually not to bad. However, I would like the correct position of the 
copy. Instead of preceding-sibling::* in the count() function, I would like to 
write something like preceding-sibling::element(node-name(.)). Unfortunately 
the processor does not allow that ;-(…

Any suggestions?

Thanks in advance
Leo



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