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Re: [xsl] Separator for xsl:number @format

2019-10-23 10:46:58
I don't think this can be achieved directly; you'll need to use some 
workaround. For example, generate the number as A#1 and then post-process to 
strip out the '#'. Alternatively, I sometimes find it works better not to use 
level=multiple, and instead use a series of calls to xsl:number for the 
individual levels.

Michael Kay

On 23 Oct 2019, at 15:41, Rick Quatro rick(_at_)rickquatro(_dot_)com 
<xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:

I am using xsl:number to format some sections. Here is my instruction:
<xsl:number level="multiple" count="part|subpart" format="A1"/>
I want my subparts to number A1, A2, A3, etc. Instead, I get A.A, A.B, A.C.
<xsl:number level="multiple" count="part|subpart" format="A&#x200b;1"/>
If I add a zero-width space to the format, I get the desired result, but I 
want to know if this is necessary. I am using XSLT 2 and Saxon 9. Thank you 
very much.
Rick Quatro
Carmen Publishing Inc.
rick(_at_)frameexpert(_dot_)com <mailto:rick(_at_)frameexpert(_dot_)com>
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