Thank you Michael. I took your advice and used a series of <xsl:number>
instructions so I don't have to use the zero-width space.
From: Michael Kay mike(_at_)saxonica(_dot_)com
<xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent: Wednesday, October 23, 2019 11:47 AM
To: xsl-list <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Subject: Re: [xsl] Separator for xsl:number @format
I don't think this can be achieved directly; you'll need to use some
workaround. For example, generate the number as A#1 and then post-process to
strip out the '#'. Alternatively, I sometimes find it works better not to
use level=multiple, and instead use a series of calls to xsl:number for the
individual levels.
Michael Kay
Saxonica
On 23 Oct 2019, at 15:41, Rick Quatro rick(_at_)rickquatro(_dot_)com
<mailto:rick(_at_)rickquatro(_dot_)com>
<xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com
<mailto:xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> > wrote:
Hi,
I am using xsl:number to format some sections. Here is my instruction:
<xsl:number level="multiple" count="part|subpart" format="A1"/>
I want my subparts to number A1, A2, A3, etc. Instead, I get A.A, A.B, A.C.
<xsl:number level="multiple" count="part|subpart" format="A​1"/>
If I add a zero-width space to the format, I get the desired result, but I
want to know if this is necessary. I am using XSLT 2 and Saxon 9. Thank you
very much.
Rick
Rick Quatro
Carmen Publishing Inc.
<mailto:rick(_at_)frameexpert(_dot_)com> rick(_at_)frameexpert(_dot_)com
585-729-6746
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