Re: [xsl] compare two node sets

On Sun, Jan 19, 2020 at 09:26:54PM -0000, Martin Honnen 
martin(_dot_)honnen(_at_)gmx(_dot_)de scripsit:
> On 19.01.2020 22:21, Wolfhart Totschnig 
> wolfhart(_dot_)totschnig(_at_)mail(_dot_)udp(_dot_)cl
> wrote:
[snip]
> > XPST0003: Unexpected token "every" at start of expression
> I think you need to put the `every` expression into parenthesis, and in
> the context of a `film` element it suffices to use child selection, so
> to simplify:
>
> count(director) eq count(author) and (every $d in director satisfies
> some $a in author satisfies deep-equal($d/*, $a/*))
You might also want to check that the stylesheet version isn't set to
1.0.  That ought to give you a different error, but if, in the
stylesheet element you have (among probably several other attributes)

<xsl:stylesheet version="1.0">

You want at least:
<xsl:stylesheet version="2.0">

And honestly
<xsl:stylesheet version="3.0">

Wouldn't hurt.

-- Graydon
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