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Re: [xsl] compare two node sets

2020-01-21 07:21:57
from [Mukul Gandhi gandhi(_dot_)mukul(_at_)gmail(_dot_)com] [Permanent Link] 
On Mon, Jan 20, 2020 at 2:19 AM Michael Kay mike(_at_)saxonica(_dot_)com <
xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:



The simplest (XPath 2.0) solution that comes to mind is

count(//director) eq count(//author) and
every $d in //director satisfies
  some $a in //author satisfies
    deep-equal($d/*, $a/*)



+1

(with the improvisation suggested by Martin)



-- 
Regards,
Mukul Gandhi

http://member.acm.org/~mukulgandhi
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