Re: [xsl] XSLT program outputs a series of items, how to insertnewlines

Hi Martin,

I gave your suggestion a try (although, since I am running a Windows machine, I 
used CRLF as the separator):

<xsl:value-of select="concat(@value, ' (', xs:annotation/xs:documentation, 
')')" separator="&#xD;&#xA;"/>

Unfortunately, in the output the items are not separated by newlines. Any 
thoughts on why that is?

/Roger

-----Original Message-----
From: Martin Honnen martin(_dot_)honnen(_at_)gmx(_dot_)de 
<xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> 
Sent: Thursday, June 25, 2020 9:17 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [EXT] Re: [xsl] XSLT program outputs a series of items, how to 
insertnewlines between each item?


On 25.06.2020 15:11, Roger L Costello costello(_at_)mitre(_dot_)org wrote:
> Hi Folks,
>
> My XSLT program has a loop. Each iteration outputs an item. I want each item 
> on a new line. The following works. Is there a better way to insert newlines 
> than by using xsl:text with the end tag on the next line?  /Roger
>
> <xsl:output method="text" />
>
> <xsl:template match="/">
>      <xsl:for-each select="//xs:simpleType[@name eq 
> 'DatumCode']//xs:enumeration">
>          <xsl:value-of select="concat(@value, ' (', 
> xs:annotation/xs:documentation, ')')/>
> <xsl:text>
> </xsl:text>
>      </xsl:for-each>
> </xsl:template>

I would use xsl:value-of separator


<xsl:value-of select="//xs:simpleType[@name eq
'DatumCode']//xs:enumeration/concat(@value, ' (',
xs:annotation/xs:documentation, ')')" separator="&#10;"/>

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