On 25.06.2020 15:25, Roger L Costello costello(_at_)mitre(_dot_)org wrote:
Hi Martin,
I gave your suggestion a try (although, since I am running a Windows machine, I
used CRLF as the separator):
<xsl:value-of select="concat(@value, ' (', xs:annotation/xs:documentation, ')')"
separator="
"/>
Unfortunately, in the output the items are not separated by newlines. Any
thoughts on why that is?
My suggestion is to replace the whole for-each with the single value-of
I posted.
-----Original Message-----
From: Martin Honnen martin(_dot_)honnen(_at_)gmx(_dot_)de
<xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent: Thursday, June 25, 2020 9:17 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [EXT] Re: [xsl] XSLT program outputs a series of items, how to
insertnewlines between each item?
On 25.06.2020 15:11, Roger L Costello costello(_at_)mitre(_dot_)org wrote:
Hi Folks,
My XSLT program has a loop. Each iteration outputs an item. I want each item on
a new line. The following works. Is there a better way to insert newlines than
by using xsl:text with the end tag on the next line? /Roger
<xsl:output method="text" />
<xsl:template match="/">
<xsl:for-each select="//xs:simpleType[@name eq
'DatumCode']//xs:enumeration">
<xsl:value-of select="concat(@value, ' (',
xs:annotation/xs:documentation, ')')/>
<xsl:text>
</xsl:text>
</xsl:for-each>
</xsl:template>
I would use xsl:value-of separator
<xsl:value-of select="//xs:simpleType[@name eq
'DatumCode']//xs:enumeration/concat(@value, ' (',
xs:annotation/xs:documentation, ')')" separator=" "/>
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