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Re: [xsl] XSLT program outputs a series of items, how to insert newlines between each item?

2020-06-25 09:35:27
Hi Roger,

I always use a variable for CR and as Martin says an xsl:value-of.
I also pass a parameter in with OS so that CR gets either Windows or Linux
separators..

Hope this hells
Graham

On Thu, 25 Jun 2020 at 15:16, Martin Honnen 
martin(_dot_)honnen(_at_)gmx(_dot_)de <
xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:


On 25.06.2020 15:11, Roger L Costello costello(_at_)mitre(_dot_)org wrote:
Hi Folks,

My XSLT program has a loop. Each iteration outputs an item. I want each
item on a new line. The following works. Is there a better way to insert
newlines than by using xsl:text with the end tag on the next line?  /Roger

<xsl:output method="text" />

<xsl:template match="/">
     <xsl:for-each select="//xs:simpleType[@name eq
'DatumCode']//xs:enumeration">
         <xsl:value-of select="concat(@value, ' (',
xs:annotation/xs:documentation, ')')/>
<xsl:text>
</xsl:text>
     </xsl:for-each>
</xsl:template>


I would use xsl:value-of separator


<xsl:value-of select="//xs:simpleType[@name eq
'DatumCode']//xs:enumeration/concat(@value, ' (',
xs:annotation/xs:documentation, ')')" separator="&#10;"/>


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