You seem to be under the misapprehension that "|" is a boolean `or` operator.
That's not the case: it forms the union of two node-sets.
Node-sets are often used in a context where they are implicitly converted to
booleans (empty node-set => false, non-empty => true), and in this situation
`boolean( NS1 | NS2 )` means the same as `boolean(NS1) or boolean(NS2)`
which may be how you got confused.
But using "|" with operands that aren't node-sets (your second and third
examples) is an error.
Michael Kay
Saxonica
On 8 Dec 2021, at 14:53, Michele R Combs mrrothen(_at_)syr(_dot_)edu
<xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:
All three of these constructions appear to be valid (this is xsl 1.0, sorry
for being antiquated!). Will there be differences in the output? If not, is
one option “better” than the others, and if so why? I’m guessing that there
are no differences in output, and that option 3 is better because more
concise. Am I right?
“or” statements in the select condition:
<xsl:for-each select="child::*[@level = 'collection'] | child::*[@level =
'recordgrp'] | child::*[@level = 'series'] | child::*[@level = 'subseries']">
“or” statements inside the node description [ ]
<xsl:for-each select="child::*[@level = 'collection' | @level = 'recordgrp' |
@level = 'series' | @level = 'subseries']">
“or” statements inside the attribute match
<xsl:for-each select="child::*[@level = 'collection' | 'recordgrp' | 'series'
| 'subseries']">
Michele
+++++++++
Michele Combs | Lead Archivist
Special Collections Research Center
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