Ouch the send button hit itself sorry!
2nd expression rewritten:
<xsl:for-each select="child::*[@level = 'series' or @level = 'subseries']">
but we need XPath 2.0 to say
<xsl:for-each select="child::*[@level = ('series', 'subseries')]">
Cheers, Wendell
On Wed, Dec 8, 2021 at 11:16 AM Wendell Piez
<wapiez(_at_)wendellpiez(_dot_)com> wrote:
Michele,
As Eliot notes, the pipe operator in XPath is shorthand for "union", not
"or", although there are places (such as a match pattern) when a union
("give me As and Bs") can look and work like an "or" ("give me things that
are A or B").
So spelled out into long syntax (and keeping only two cases) your first
for-each looks like
<xsl:for-each select="child::*[attribute::level = 'series'] union
child::*[attribute::level = 'subseries']">
“or” statements inside the attribute match
<xsl:for-each select="child::*[@level = 'collection' | 'recordgrp' |
'series' | 'subseries']">
On Wed, Dec 8, 2021 at 9:54 AM Michele R Combs mrrothen(_at_)syr(_dot_)edu <
xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:
All three of these constructions appear to be valid (this is xsl 1.0,
sorry for being antiquated!). Will there be differences in the output? If
not, is one option “better” than the others, and if so why? I’m guessing
that there are no differences in output, and that option 3 is better
because more concise. Am I right?
“or” statements in the select condition:
<xsl:for-each select="child::*[@level = 'collection'] | child::*[@level
= 'recordgrp'] | child::*[@level = 'series'] | child::*[@level =
'subseries']">
“or” statements inside the node description [ ]
<xsl:for-each select="child::*[@level = 'collection' | @level =
'recordgrp' | @level = 'series' | @level = 'subseries']">
“or” statements inside the attribute match
<xsl:for-each select="child::*[@level = 'collection' | 'recordgrp' |
'series' | 'subseries']">
Michele
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