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Re: [xsl] How to sort based on the number of child elements?

2022-05-09 12:55:57
This transformation:

<xsl:stylesheet version="1.0" xmlns:xsl="
http://www.w3.org/1999/XSL/Transform";
 xmlns:xs="http://www.w3.org/2001/XMLSchema";>
 <xsl:output omit-xml-declaration="yes" indent="yes"/>

  <xsl:template match="node()|@*">
    <xsl:copy>
      <xsl:apply-templates select="node()|@*"/>
    </xsl:copy>
  </xsl:template>

  <xsl:template match="/*">
    <xsl:copy>
      <xsl:apply-templates select="xs:element">
         <xsl:sort
select="count(xs:complexType[1]/xs:sequence[1]/xs:element)"
order="descending"/>
      </xsl:apply-templates>
    </xsl:copy>
  </xsl:template>
</xsl:stylesheet>

When applied on the provided XML document:

<xs:choice xmlns:xs="http://www.w3.org/2001/XMLSchema";>
  <xs:element name="MilitaryDayTime">
    <xs:complexType>
      <xs:sequence>
        <xs:element name="Day" type="xs:string"/>
        <xs:element name="HourTime" type="xs:string"/>
        <xs:element name="MinuteTime" type="xs:string"/>
        <xs:element name="TimeZone" type="xs:string"/>
     </xs:sequence>
   </xs:complexType>
 </xs:element>
<xs:element name="DateTimeGroup">
  <xs:complexType>
    <xs:sequence>
      <xs:element name="Day" type="xs:string"/>
       <xs:element name="HourTime" type="xs:string"/>
      <xs:element name="MinuteTime" type="xs:string"/>
      <xs:element name="TimeZone" type="xs:string"/>
      <xs:element name="MonthName" type="xs:string"/>
      <xs:element name="Year" type="xs:string"/>
    </xs:sequence>
  </xs:complexType>
 </xs:element>
</xs:choice>

produces the wanted result:

<xs:choice xmlns:xs="http://www.w3.org/2001/XMLSchema";>
   <xs:element name="DateTimeGroup">
   <xs:complexType>
     <xs:sequence>
       <xs:element name="Day" type="xs:string"/>
       <xs:element name="HourTime" type="xs:string"/>
       <xs:element name="MinuteTime" type="xs:string"/>
       <xs:element name="TimeZone" type="xs:string"/>
       <xs:element name="MonthName" type="xs:string"/>
       <xs:element name="Year" type="xs:string"/>
     </xs:sequence>
   </xs:complexType>
   </xs:element>
   <xs:element name="MilitaryDayTime">
   <xs:complexType>
     <xs:sequence>
       <xs:element name="Day" type="xs:string"/>
       <xs:element name="HourTime" type="xs:string"/>
       <xs:element name="MinuteTime" type="xs:string"/>
       <xs:element name="TimeZone" type="xs:string"/>
     </xs:sequence>
   </xs:complexType>
    </xs:element>
</xs:choice>

Hope this helps.

Dimitre

On Mon, May 9, 2022 at 10:31 AM Roger L Costello costello(_at_)mitre(_dot_)org <
xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:

Hi Folks,

I have an XML Schema that contains a xs:choice. I want to sort the
branches of the choice, in longest-to-shortest order.

Here is a xs:choice with two branches:

<xs:choice>
    <xs:element name="MilitaryDayTime">
        <xs:complexType>
            <xs:sequence>
                <xs:element name="Day" type="xs:string"/>
                <xs:element name="HourTime" type="xs:string"/>
                <xs:element name="MinuteTime" type="xs:string"/>
                <xs:element name="TimeZone" type="xs:string"/>
            </xs:sequence>
        </xs:complexType>
    </xs:element>
    <xs:element name="DateTimeGroup">
        <xs:complexType>
            <xs:sequence>
                <xs:element name="Day" type="xs:string"/>
                <xs:element name="HourTime" type="xs:string"/>
                <xs:element name="MinuteTime" type="xs:string"/>
                <xs:element name="TimeZone" type="xs:string"/>
                <xs:element name="MonthName" type="xs:string"/>
                <xs:element name="Year" type="xs:string"/>
            </xs:sequence>
        </xs:complexType>
    </xs:element>
</xs:choice>

The first branch is an element with 4 child elements. The second branch is
an element with 6 child elements. So sorting the branches
longest-to-shortest will result in reversing the order of the branches.

I cannot use xsl:sort for this, right?

Is there an easy solution to this task?

/Roger




-- 
Cheers,
Dimitre Novatchev
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