I cannot use xsl:sort for this, right?
Why not?
See my reply using <xsl:sort> to solve the problem.
On Mon, May 9, 2022 at 10:31 AM Roger L Costello costello(_at_)mitre(_dot_)org <
xsl-list-service(_at_)lists(_dot_)mulberrytech(_dot_)com> wrote:
Hi Folks,
I have an XML Schema that contains a xs:choice. I want to sort the
branches of the choice, in longest-to-shortest order.
Here is a xs:choice with two branches:
<xs:choice>
<xs:element name="MilitaryDayTime">
<xs:complexType>
<xs:sequence>
<xs:element name="Day" type="xs:string"/>
<xs:element name="HourTime" type="xs:string"/>
<xs:element name="MinuteTime" type="xs:string"/>
<xs:element name="TimeZone" type="xs:string"/>
</xs:sequence>
</xs:complexType>
</xs:element>
<xs:element name="DateTimeGroup">
<xs:complexType>
<xs:sequence>
<xs:element name="Day" type="xs:string"/>
<xs:element name="HourTime" type="xs:string"/>
<xs:element name="MinuteTime" type="xs:string"/>
<xs:element name="TimeZone" type="xs:string"/>
<xs:element name="MonthName" type="xs:string"/>
<xs:element name="Year" type="xs:string"/>
</xs:sequence>
</xs:complexType>
</xs:element>
</xs:choice>
The first branch is an element with 4 child elements. The second branch is
an element with 6 child elements. So sorting the branches
longest-to-shortest will result in reversing the order of the branches.
I cannot use xsl:sort for this, right?
Is there an easy solution to this task?
/Roger
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Dimitre Novatchev
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