MA(n)*n + S(n+1)
MA(n+1)= ---------------- Where MA(x) is arithmetic mean at step x
n+1 with S(x) being actual score at step x
If n is constant, this doesn't really compute an arithmetic mean, but
the so-called "decaying average",
But the formula as written - ie, where n is the same n throughout -
*does* compute the arithmetic mean. (Induction hypothesis: MA(n) is
the arithmetic mean of S(i<=n). Induction step: MA(n)*n is then
sum(S(i<=n)), making the numerator sum(S(i<=n+1)) and MA(n+1) the
correct mean.)
I see no reason to insist on misreading the formula in order to get
something other than what the author claimed, when reading it as
written does get what was claimed.
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