Re: I'm a lazy sod

Paul Chvostek skribis:

>   * 1^1 $ B ?? ${FOO}
>   * $ 1^1 B ?? ${FOO}
It is of course possible to do

  :0B
  * $ 1^1 $\FOO

but I assume you have a reason to want to use the B in the condition: 

  *$ B ?? 1^1 $\FOO


-- 
Affijn, Ruud

Easy people don't care too much.

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