On Thu, 04 Mar 2004, 03:42 GMT-08 (12:42 local time) Professional
Software Engineering wrote:
At 11:20 2004-03-04 +0100, Robert Allerstorfer wrote:
why so complicated? A one-line condition can first tell you if the ZIP
is encrypted or not:
zipinfo file.zip | sed -ne '2p' | sed -ne 's/^[^ ]* *[^ ]* *[^ ]* *[^ ]*
*\(.\).*/\1/p'
Your "one line" involves a shell, and three program invocations (two of
which could be combined). Talk about complicated.
Why resort to a command pipeline when it can be performed with a SINGLE
program invocation?
ZIPSTATE=`zipinfo file.zip`
The one-liner I posted is a quick hack to be executed on *the shell*,
and should only demonstrate how the principe of determining a
encrypted ZIP could work directly, without fooling a program and make
the decision based on an error the program may return. It has never
been intended to be used directly in a procmail recipe.
Also, consider what happens if using your suggestion and file.zip
contains thousand or more files (which can even be zero byte ones): a
buffer overflow will most likely arise...
rob.
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