A lot of thanks. I don't know that I could use XPath inside this expression.
Missatge citat per: Nirmala R <nirmala(_dot_)r(_at_)sisl(_dot_)co(_dot_)in>:
Hello,
You can substring operation instead of having wildcard in the
expression.
like "dato[substring(@id,1,5)= 'imagen']" in the Xpath query.
Is that what you want?
Regards,
Nirmala
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com]On Behalf Of
Marcial
Atienzar Navarro
Sent: Monday, October 21, 2002 1:34 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] How can i detect differents nodes with a similar name?
Hello,
I need to do this:
I have, for example, this 2 tags:
<dato id="imagen_1">aaaa</dato>
<dato id="imagen_2">bbbb</dato>
It's possible to do something like this:
<xsl:template match="dato[(_at_)id= 'imagen*']">OK</xsl:template>
And make it works, is to say, the xsl must detect the 2 nodes: imagen_1
and
imagen_2.
A lot of thanks,
Marcial Atienzar
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list