Hello Juan,
the error is obviously:
Juan Carlos Gonzalez wrote:
I'm transforming on the server, using MSXML 3.0.
This is my stylesheet:
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
<xsl:output method="html"/>
<xsl:template match="/">
<xsl:apply-templates select="/Products/npc"/>
</xsl:template>
<xsl:template match="npc">
<xsl:copy>
<xsl:apply-templates select="@*"/>
<xsl:copy-of select="*"/>
Here you copy all elements without any processing, so you never apply
templates on @URL. Change it to <xsl:apply-templates select="*"/> and
the the template match to "*". Then it shell work.
Joerg
</xsl:copy>
</xsl:template>
<xsl:template match="@*">
<xsl:copy-of select="."/>
</xsl:template>
<xsl:template match="@URL">
<xsl:attribute
name="URL">http://www.mydomain.com</xsl:attribute>
<!-- or
<xsl:copy>http://www.mydomain.com</xsl:copy>
-->
</xsl:template>
</xsl:stylesheet>
Source file:
<Products>
<npc CatId="01" Descr="Accessories">
<p Price="5.61" Sku="C45-4022" ManfPartNo="4502"
URL="http://www.xxx.com/item.asp?sku=C45-4022" />
<p Price="9.99" Sku="I30-1032" ManfPartNo="6333"
URL="http://www.xxx.com/item.asp?sku=I30-1032"/>
</npc>
</Products>
I just want to replace once I copy the content of the
URL attribute.
Thanks again.
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list