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RE: Copying nodes

2002-12-10 14:46:10
I'm transforming on the server, using MSXML 3.0.

This is my stylesheet:

<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; >
<xsl:output method="html"/>

<xsl:template match="/">
  <xsl:apply-templates select="/Products/npc"/>
</xsl:template>

<xsl:template match="npc">
  <xsl:copy>
    <xsl:apply-templates select="@*"/> 
    <xsl:copy-of select="*"/>
  </xsl:copy>           
</xsl:template>

<xsl:template match="@*">
  <xsl:copy-of select="."/>
</xsl:template>

<xsl:template match="@URL">
   <xsl:attribute
name="URL">http://www.mydomain.com</xsl:attribute>
<!--                or
        <xsl:copy>http://www.mydomain.com</xsl:copy>
-->
</xsl:template>

</xsl:stylesheet>

Source file:

<Products>
<npc CatId="01" Descr="Accessories">
<p Price="5.61" Sku="C45-4022" ManfPartNo="4502"
URL="http://www.xxx.com/item.asp?sku=C45-4022"; />
<p Price="9.99" Sku="I30-1032" ManfPartNo="6333"
URL="http://www.xxx.com/item.asp?sku=I30-1032"/> 
</npc>
</Products>

I just want to replace once I copy the content of the
URL attribute.

Thanks again.


 
--- Michael Kay <michael(_dot_)h(_dot_)kay(_at_)ntlworld(_dot_)com> wrote:

The code that you sent me did not change the value
of
the URL attribute within the copied node. Any
other suggestions?

Please post your complete stylesheet and source
document, tell us what
processor you are using, and show us the results you
are getting.

This code is correct, so either you are running it
incorrectly, or you
are using a duff processor.

Michael Kay


--- Americo_Albuquerque
<aalbuquerque(_at_)viseu(_dot_)ipiaget(_dot_)pt> wrote:
Hi.
I don't know what you trying to do but try this,
it
will copy everything
and will change your attribute:

<xsl:template match="categ">
  <xsl:copy>
    <xsl:apply-templates select="@*"/> 
    <xsl:copy-of select="*"/>
  </xsl:copy>             
</xsl:template>

<xsl:template match="@*">
  <xsl:copy-of select="."/>
</xsl:template>

<xsl:template match="@URL">  
<xsl:copy>http://www.mydomain.com</xsl:copy>
</xsl:template>


-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com]
On
Behalf Of Juan Carlos
Gonzalez
Sent: terca-feira, 10 de Dezembro de 2002 18:11
To: XSL-List(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] Copying nodes


I'm sorry but still doesn not work.

-----Original Message-----
From: Americo Albuquerque
[mailto:aalbuquerque(_at_)viseu(_dot_)ipiaget(_dot_)pt]
Sent: Tuesday, December 10, 2002 11:42 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] Copying nodes


Hi.
Use:
<xsl:template match="@URL"> 
<xsl:copy>http://www.mydomain.com</xsl:copy>
</xsl:template>

Hope that this helps

-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com]
On
Behalf Of Juan Carlos
Gonzalez
Sent: terca-feira, 10 de Dezembro de 2002 14:44
To: XSL-List(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Copying nodes


Hi:

I have the following templates for copying nodes
and
it's attributes which work OK:

<xsl:template match="/">
  <xsl:apply-templates select="/root/categ"/>
</xsl:template>

<xsl:template match="categ|@*">
  <xsl:copy>
    <xsl:apply-templates select="@*"/> 
    <xsl:copy-of select="*"/>
  </xsl:copy>             
</xsl:template>

What I'm trying to do is to change the value for
a
specific attribute, for that purpose I have
created
another template but it doesn't seem to execute
at
all:

<xsl:template match="@URL">
   http://www.mydomain.com
<!-- or 
    <xsl:copy-of
select="http://www.mydomain.com"/>
-->  
</xsl:template>
 
Thanks.




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