The output you are trying to achieve is not well-formed HTML, so the
only way you can construct it with the HTML output method is to use
disable-output-escaping.
The <?---?> thing is not a processing instruction (because PIs can't
occur inside attributes); if it were a PI, you would create it using
xsl:processing-instruction, not xsl:pi.
Michael Kay
Software AG
home: Michael(_dot_)H(_dot_)Kay(_at_)ntlworld(_dot_)com
work: Michael(_dot_)Kay(_at_)softwareag(_dot_)com
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
Jens Laufer
Sent: 02 December 2002 10:58
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] xsl:attribute problem
Hi all,
I need to solve this problem:
I want to create this output from a XML-source and a XSL-stylesheet:
<---snippet---!>
<a href="mailto: <?php echo $email?>"><?php echo $email?></a>
<---snippet---!>
I am using this XSL-stylesheet:
<---snippet---!>
<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">
<xsl:output method="html" indent="yes"/>
<xsl:template match="/document">
<a>
<xsl:attribute name="href">mailto:<xsl:apply-templates
select="email"/></xsl:attribute>
<xsl:apply-templates select="email"/>
</a>
</xsl:template>
<xsl:template match='email'>
<xsl:apply-templates/>
</xsl:template>
<xsl:template match='*|@*'>
<xsl:copy>
<xsl:apply-templates select='node()|@*'/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
<---snippet---!>
I tried this XML to get that output:
======================================================================
XML:
<?xml version="1.0" encoding="iso-8859-1"?>
<document>
<email><xsl:pi value="php">echo $email</xsl:pi></email> </document>
I get this error:
java.io.IOException: /home/jens/test/test.xsl:7: element
`xsl:pi' is not
allowed inside attribute `href'.
================================================================
XML:
<?xml version="1.0" encoding="iso-8859-1"?>
<document>
<email><script language="php">echo $email</script></email>
</document>
I get this error:
java.io.IOException: /home/jens/test/test.xsl:7: element
`script' is not
allowed inside attribute `href'.
=================================================================
XML:
<?xml version="1.0" encoding="iso-8859-1"?>
<document>
<email><?php echo $email ?></email>
</document>
I get this output:
<a href="mailto:";></a>
=================================================================
XML:
<?xml version="1.0" encoding="iso-8859-1"?>
<document>
<email><?php echo $email ?<</email>
I get this output:
<a href="mailto:<?php echo $email ?<"><?php echo $email
?<</a>
==================================================================
I don't really know how to solve that and I am struggling
around with it since
a while now...
Actually I don't want to change the stylesheet too much,
because with the
current stylesheet it should be possible to swap quickly
technologies: You just change e.g. <?php echo $test?> into
<%=test%> and you can use jsp... So there should be no
"technologiy" infromation in the stylesheet.
I think especially the attributes are making a lot of
problems... Any ideas? Thanks in advance! Jens
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