I too have hit this problem, perhaps I have overlooked something here
but an xs:copy-of or a deep copy will return an exact copy:
Given an input of:
<mytag>blabla <foo>foo text</foo> other stuff </mytag>
an xsl:copy-of will result in:
<mytag>blabla <foo>foo text</foo> other stuff </mytag>
ie , the same, which is not necessarily what you want, ie you may want:
<peter name="yes" att="yes">
blabla <foo>foo text</foo> other stuff
</peter>
so how would I get this, ie what would the xsl be?
Regards Peewee
-----Original Message-----
From: David(_dot_)Pawson(_at_)rnib(_dot_)org(_dot_)uk
[mailto:David(_dot_)Pawson(_at_)rnib(_dot_)org(_dot_)uk]
Sent: 21 March 2003 14:07
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] how to insert the *complete* content of a node
<grin/> Got me too!
Try
<xsl:template match="mytag">
<xsl:copy>
<xsl:copy-of select="*|@*"/>
</xsl:copy>
</
Instead of copying the value of the contents,
copies the contents and its markup.
HTH DaveP
I've a problem I can't resolve:
I have some node that may contain *any* text, including xml/html-like
text.
I mean something like:
<mytag>blabla <foo>foo text</foo> other stuff </mytag>
I have to produce the complete content of the mytag tag:
blabla <foo>foo text</foo> other stuff
I've tried some combination, but I still can't do it,
the problem is that I do not know *which* tags and *how many* could be
nested in the mytag tag.
may anyone help me?
thanks,
Danilo.
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