"John Chen" <jchen(_at_)parasoft(_dot_)com> wrote in message
news:5(_dot_)0(_dot_)2(_dot_)1(_dot_)0(_dot_)20030304115132(_dot_)00b604e0(_at_)mail(_dot_)parasoft(_dot_)com(_dot_)(_dot_)(_dot_)
I would like to create an XSL that takes an XML file and returns it as its
output. Is that easy to do?
Yes, use:
<xsl:copy-of select="/"/>
A lot more useful (because it can be overridden) is the following template,
known as the "identity transformation":
http://www.w3.org/TR/xslt#copying
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
=====
Cheers,
Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list