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RE: Xpath and for-each looping

2003-05-18 10:00:32
First, how to sort? I used an old database trick.  The sort key is a 
unique combination of month, day, and year like this -

key = day + 50 * month + (2000 + year)


Tom, how would this key differentiate between 5th may 2003 
(05-05-2003) and 
8th of may 2000 (08-05-2000) ? I would get 5 + 250 + 2000 + 
03 = 2258 = 8 + 
250 + 2000 + 00.

I would imagine something like: key= day + 50 * month + 1000 
* year would do it (did you mean 2000 * year?).

What's wrong with the simpler technique of simply removing the
punctuation, so 2003-05-08 sorts as 20030508?

Michael Kay


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