RE: Join XMLs with XLST with ralative data2003-06-05 01:58:17Hi, I am using join.xslt <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:key name="rows-bstkcode" match="bstkcode" use="bstkcode" /> The key should be <xsl:key name="rows-bstkcode" match="name" use="bstkcode" /> <xsl:for-each select="$x_22/STKAVAILABLE/STKMAST"> If you only want the STKCODE 31, i.e. the first one, this should be <xsl:for-each select="$x_22/STKAVAILABLE/STKMAST[1]">
This should be e.g.
<xsl:for-each select="$buy22">
<xsl:for-each select="key('rows-bstkcode', $STKCODE)">
<xsl:copy>
<xsl:copy-of select="@id" />
</xsl:copy>
</xsl:for-each>
Because what you had would output
<tran>
<STKMAST Alias="01" STKCODE="31">
<address/>
<address/>
</STKMAST>
</tran>
Cheers,
Jarno - Claire Voyant: Love the Giver (remix by Eskil Simonsson of Covenant)
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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