Hi again,
Section 7.5 of the Rec says:
When the current node is an attribute, then if it would be an error to use
xsl:attribute to create an attribute with the same name as the current node,
then it is also an error to use xsl:copy (see [7.1.3 Creating Attributes
with xsl:attribute]).
I took this to mean that xsl:copy won't work just as using xsl:attribute
with the same name as the current node...however, the below template works
(replacing same template from my previous post). When xsl:copy didn't work
and I found that definition I didn't initially test this approach...my gut
told me to try it anyways after looking around...
<xsl:template match="@myAtt">
<xsl:attribute name="myAtt">
<xsl:value-of select="'hi there'"/>
</xsl:attribute>
</xsl:template>
Well, I guess I'm on my way, but if anybody has comments as to this
approach, I would more than welcome them.
Thanks,
Benjamin
From: "Benjamin Farrow" <lovinjess(_at_)hotmail(_dot_)com>
Reply-To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] template match on attribute, copy but change value
Date: Thu, 10 Jul 2003 15:51:08 -0700
Hi,
I'm attempting to find a single attribute and change it's value. I
thought this should be simple, but it just doesn't seem to be working.
Looking at the Rec it says that xsl:copy is not allowed to copy the
attribute and change it's value (what it looks like in the archives that I
found as well). So my question is, can I use the identity transform, then
have a template matching a specific attribute and copy the attribute to the
result, but change it's value?
XML File:
<test>
<Element myAtt="test">
<child/>
</Element>
</test>
XSL File:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/">
<xsl:apply-templates select="*"/>
</xsl:template>
<xsl:template match="@myAtt">
<xsl:copy> <!-- this is ignored and will not let me change the value
-->
<xsl:value-of select="'hi there'"/>
</xsl:copy>
</xsl:template>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Expected Output:
<test>
<Element myAtt="hi there">
<child/>
</Element>
</test>
Thanks for any comments,
Benjamin
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