Hi Julian,
i understand that you wish to apply an XSL to a XML
file, and supply imageNum parameter with the URL.
Instead of trying to do transformation on browser as
http://bla.bla/batman.xml?imageNum=3 , you may shift
your XSLT processsing on server side. The advantage is
that *this will work with all the browsers*. For e.g.
if you are in a position to use JSP, you can easily do
http://bla.bla/sompage.jsp?imageNum=3 . Then in this
JSP you can easily extract imageNum value using
request.getParameter("imageNum") and then can call a
Java XSLT processor and return the result of transform
to browser.
Regards,
Mukul
--- Julian Wood <woodj(_at_)ucalgary(_dot_)ca> wrote:
Hi Mukul,
Thanks for your response. Unfortunately this is a
user-generated
parameter (from another local (ie on CD) web page),
so I don't see how
I can write their choice to a file, or even
manipulate a file so it
reflects their choice, such that I could read it in
via document(). I
was thinking sending it as a get parameter in the
URL would be best,
but still no luck in getting it back again in the
next xsl document.
Regards,
J
On Sunday, August 10, 2003, at 10:40 PM, Mukul
Gandhi wrote:
Hi Julian,
i don't know whether it will really be possible
to
get parameter value as you want. But i can think
of an
alternative approach. You can create another XML
file
for e.g. param.xml having something like --
<?xml version="1.0" encoding="UTF-8"?>
<param>3</param>
In your XSL you can use document() function to
access
param.xml and the <param> tag's value..
Regards,
Mukul
--
Julian Wood
Programmer/Analyst
Learning Commons, University of Calgary
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