You are trying to create one node in the output (X) corresponding to two
nodes in the input (C and D). I classify all such problems as grouping
problems, though this might be a rather simple one (but that depends on
whether the range of possible inputs you need to deal with can be
correctly inferred from your example).
The basic approach is that you need to fire one template rule that
processes the group as a whole. The solution might look like this:
<xsl:template match="C">
<X>
<xsl:copy-of select="."/>
<xsl:copy-of select="following-sibling::D[1]"/>
</X>
</xsl:template>
<xsl:template match="D"/>
Michael Kay
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
Romeo Disca
Sent: 16 September 2003 16:36
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] [recursion pattern] sophisticated problem
Hi,
I'm trying to find a solution for copying an existing tree
with an identity transformation. Some nodes should be
modified. For the most tasks I have a solution but this one.
Transforming a node like this:
----------------
input tree:
/context-node/
+-/ A /
+-/ B /
+-/ C mode="x" /
+-/ D mode="x" /
+-/ E /
+-/ F /
-----------------
result tree:
/context-node/
+-/ A /
+-/ B /
+-/ X /
+-/ C mode="x" /
+-/ D mode="x" /
+-/ E /
+-/ F /
===========
My approach uses the recursion pattern (Kay 2001 p. 614) to
iterate through the child node list. The best I've got so far is:
-----------------
result tree:
/context-node/
+-/ A /
+-/ B /
+-/ X /
+-/ C mode="x" /
+-/ D mode="x" /
+-/ E /
+-/ F /
===========
I think this is so because the recursion levels lay upon each
other and inserting the X node in one effects the rest node
list even if I test for 'not mode' Nodes.
Question: Is the recursion pattern the best way to do the job
and I only need to do more reasoning? Or, does anyone know an
alternative way to do that?
Romeo
--
Romeo Disca
Email: romeo(_dot_)disca(_at_)t-online(_dot_)de
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