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Re: Copying XML file over using XSLT

2003-10-13 23:47:43
sorry I posted a slightly wrong XSL.. The correct one
is --

<xsl:template match="/">
   <xsl:copy-of select="." />
</xsl:template>

The previous one is also working, but this -- is
better..

Regards,
Mukul

--- Mukul Gandhi <mukulgw3(_at_)yahoo(_dot_)com> wrote:
Hi Navid,
 Below is the XSL..

This is an identity transform --

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" version="1.0"
encoding="UTF-8" indent="yes"/>
      
<xsl:template match="/">
   <xsl:copy-of select="node() | @*" />
</xsl:template>

</xsl:stylesheet>

Regards,
Mukul

--- "Navid M." <navid89(_at_)yahoo(_dot_)com> wrote:
Hello,

Is there a short cut for copying all the content
of
my
XML file to an XHTML file using XSLT?

i.e. I want to create an XSLT file that will take
the
content of an XML file and put it in another file
exactly as it appears.

Any help would be greatly appreciated.

Thanks,
 Navid M.

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__________________________________
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 XSL-List info and archive: 
http://www.mulberrytech.com/xsl/xsl-list



__________________________________
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