The first thing I spotted was an un-closed element, the final "<hanvisning>".
Eliminate or fix that in order to get an XML document. A document that isn't
well-formed, isn't XML.
Next I noticed that your encoding attribute value was in lower case. It should
read "UTF-8".
To get to the heart of your problem, when you don't specify a template to use
in processing a node, the default template is applied. That built-in template
copies the text value of an un-matched node to the output. In this case, the
text value of <titel>. By adding a "no-op" template that matches <titel>, the
output will be suppressed:
<xsl:template match="titel" />
The next thing I noticed was that your template matches "kapitel/hanvisning".
The <hanvisning> element has no child elements.
I am a little puzzled as to why the <titel> element is being processed. It is
not a child of <hanvisning>. I had always thought that the default template was
applied when <xsl:apply-templates /> is used, but it seems that is incorrect.
Perhaps one of those better acquainted with the XSL spec can explain it to us.
--
Charles Knell
cknell(_at_)onebox(_dot_)com - email
-----Original Message-----
From: Trevor Majic <majic87(_at_)hotmail(_dot_)com>
Sent: Wed, 11 Aug 2004 13:57:39 -0500
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Omit Data While Using Copy
How would I be able to display all of the data from the following xml file,
EXCEPT for the <titel> text? (see xml example below which is one of 1200)
<?xml version="1.0"?><?xml:stylesheet type='text/xsl' href='manual.xsl'?>
<kapitel><titel>Measures every 10 percussion hours</titel><text/><hanvisning
from="ID(SEUHS-SLAGVT-10-MATARE13)">Feeder</hanvisning><text/><hanvisning
from="ID(SEUHS-SLAGVT-10-BOM19)">Boom</hanvisning><text/><hanvisning></kapitel>
I can use xsl:copy and select=node() to display everything, but no matter
what I try, I can't seem to keep the <titel> from displaying. If I try to
just use match, I am only able to display "Feeder".
This is the basic xsl I was working from:
<?xml version='1.0' encoding='utf-8' ?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="kapitel/hanvisning">
<xsl:copy>
<xsl:value-of select="node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
If you respond to this, please be fairly descriptive, as I am very new to
xsl.
Thanks in advance,
Trevor
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