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Omit Data While Using Copy

2004-08-11 11:57:39
How would I be able to display all of the data from the following xml file, EXCEPT for the <titel> text? (see xml example below ? which is one of 1200)

<?xml version="1.0"?><?xml:stylesheet type='text/xsl' href='manual.xsl'?>
<kapitel><titel>Measures every 10 percussion hours</titel><text/><hanvisning from="ID(SEUHS-SLAGVT-10-MATARE13)">Feeder</hanvisning><text/><hanvisning from="ID(SEUHS-SLAGVT-10-BOM19)">Boom</hanvisning><text/><hanvisning></kapitel>


I can use xsl:copy and select=node() to display everything, but no matter what I try, I can't seem to keep the <titel> from displaying. If I try to just use match, I am only able to display "Feeder".

This is the basic xsl I was working from:

<?xml version='1.0' encoding='utf-8' ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
 <xsl:template match="kapitel/hanvisning">
    <xsl:copy>
        <xsl:value-of select="node()"/>
    </xsl:copy>
 </xsl:template>
</xsl:stylesheet>


If you respond to this, please be fairly descriptive, as I am very new to xsl.

Thanks in advance,
Trevor

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