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Re: Omit Data While Using Copy

2004-08-11 13:13:17
Here is a good start:
http://www.dpawson.co.uk/xsl/sect2/N1930.html#d2955e100

basically it is a modified identity transform.

On Wed, 11 Aug 2004 13:57:39 -0500, Trevor Majic 
<majic87(_at_)hotmail(_dot_)com> wrote:
How would I be able to display all of the data from the following xml file,
EXCEPT for the <titel> text? (see xml example below ? which is one of 1200)

<?xml version="1.0"?><?xml:stylesheet type='text/xsl' href='manual.xsl'?>
<kapitel><titel>Measures every 10 percussion hours</titel><text/><hanvisning
from="ID(SEUHS-SLAGVT-10-MATARE13)">Feeder</hanvisning><text/><hanvisning
from="ID(SEUHS-SLAGVT-10-BOM19)">Boom</hanvisning><text/><hanvisning></kapitel>

I can use xsl:copy and select=node() to display everything, but no matter
what I try, I can't seem to keep the <titel> from displaying.  If I try to
just use match, I am only able to display "Feeder".

This is the basic xsl I was working from:

<?xml version='1.0' encoding='utf-8' ?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
 <xsl:template match="kapitel/hanvisning">
    <xsl:copy>
       <xsl:value-of select="node()"/>
    </xsl:copy>
 </xsl:template>
</xsl:stylesheet>

If you respond to this, please be fairly descriptive, as I am very new to
xsl.

Thanks in advance,
Trevor

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