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Re: Xalan bug?
2004-12-02 19:35:41
Hi Geert,
Thanks for your observations..
Please note: I am getting correct result for
group-size of 1,2,3 & 4. But with 5 and above, result
is wrong(Only with Xalan; among Xalan-J2.6.0, Saxon 8,
and MSXSL 4 with whom I tested).
One another interesting observation is that, in this
part of the code
<!-- display group members -->
<xsl:for-each select=". |
preceding-sibling::node[position() <= ($group-size
- 1)]">
<xsl:value-of select="." />
<xsl:if test="(position() mod $group-size) !=
0">
<xsl:text>,</xsl:text>
</xsl:if>
</xsl:for-each>
I wanted to generate , (commas) - to seperate group
members, actually with this code
<xsl:if test="position() != last()">
<xsl:text>,</xsl:text>
</xsl:if>
But this is not working..
So I wrote,
<xsl:if test="(position() mod $group-size) != 0">
Is'nt this surprising?
Regards,
Mukul
--- Geert Josten <Geert(_dot_)Josten(_at_)daidalos(_dot_)nl> wrote:
Hi Mukul,
The trouble rests in the expression that takes the
preceding nodes that sound belong in the last
group together with the last node:
<xsl:for-each select=". |
preceding-sibling::node[position() < $n]">
I'm very uncertain on what the XPath rec sais on how
position() should be interpreted. I tried to
wrap preceding-sibling::node in braces, but that
results in them being put back into doc order (as
it should!), so you get a in the last group instead
of one of the last... :-P
Considering that preceding-sibling::node is failing,
one should expect that only the left part of
the union (.) returns a value. But, the result is
_not_ showing the last node, but the first of that
last group (which is correct). Moreover, a ',' is
shown, so the context list is filled with more
than one node! The for-each is definitely failing!!!
A less mind boggling expression, that works with all
parsers as well (I guess) is:
<xsl:for-each select="../node[position() >
$m]">
with m defined as:
<xsl:variable name="m" select="floor(count(node)
div $group-size) * $group-size" />
Though I really think, you have conceived a complex
solution for a not necessarily that complex a
problem...
Cheers,
Geert
Mukul Gandhi wrote:
I have added some comments in my logic(shown
below) to
help in understanding..
<?xml version="1.0"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">
<xsl:output method="text" />
<xsl:param name="group-size" select="3" />
<xsl:template match="/Parent">
<!-- calculate the no of "node" elements, which
are
left as a fraction; which are to be displayed in
the
last group -->
<xsl:variable name="n" select="count(node) -
(floor((count(node) div $group-size)) *
$group-size)"
/>
<xsl:for-each select="node">
<!-- determine group boundary; this if test
stops
at the last "node" element of the group -->
<xsl:if test="(position() mod $group-size) =
0">
group <xsl:value-of
select="floor(position()
div $group-size)" /><xsl:text> - </xsl:text>
<!-- display group members -->
<xsl:for-each select=". |
preceding-sibling::node[position() <=
($group-size
- 1)]">
<xsl:value-of select="." /><xsl:if
test="(position() mod $group-size) !=
0"><xsl:text>,</xsl:text></xsl:if>
</xsl:for-each>
<xsl:text>
</xsl:text>
</xsl:if>
<!-- this if test processes the last group;
whose
number of group members will be less than the
group-size -->
<xsl:if test="((position() = last()) and
((position() mod $group-size) != 0))">
group <xsl:value-of
select="floor(position()
div $group-size) + 1" /><xsl:text> - </xsl:text>
<xsl:for-each select=". |
preceding-sibling::node[position() < $n]">
<xsl:value-of select="." /><xsl:if
test="position() !=
last()"><xsl:text>,</xsl:text></xsl:if>
</xsl:for-each>
<xsl:text>
</xsl:text>
</xsl:if>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
I would be happy to see any discussion on this
post..
Regards,
Mukul
PS: I have posted it as a bug on Xalan site.
--- Mukul Gandhi <mukul_gandhi(_at_)yahoo(_dot_)com> wrote:
Hello,
I was solving a problem posted by a user at
microsoft.public.xsl newsgroup. I seem to have
been
hit by a Xalan bug(Xalan-J 2.6.0), which I wish to
confirm with members here..
The problem posted was -
Subject: Grouping by two or any number
--------------------------------------
i have the following xml
<Parent>
<node>a</node>
<node>s</node>
<node>d</node>
<node>f</node>
<node>g</node>
<node>h</node>
<node>j</node>
<node>k</node>
<node>l</node>
</Parent>
Need to print in following format (into groups of
two)
group 1 - a,s
group 2 - d,f
group 3 - g,h
group 4 - j,k
group 5 - l
I wrote the following stylesheet -
<?xml version="1.0"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">
<xsl:output method="text" />
<xsl:param name="group-size" select="3" />
<xsl:template match="/Parent">
<xsl:variable name="n" select="count(node) -
(floor((count(node) div $group-size)) *
$group-size)"
/>
<xsl:for-each select="node">
<xsl:if test="(position() mod $group-size) =
0">
group <xsl:value-of
select="floor(position()
div $group-size)" /><xsl:text> - </xsl:text>
<xsl:for-each select=". |
preceding-sibling::node[position() <=
($group-size
- 1)]">
<xsl:value-of select="." /><xsl:if
test="(position() mod $group-size) !=
0"><xsl:text>,</xsl:text></xsl:if>
</xsl:for-each>
<xsl:text>
</xsl:text>
</xsl:if>
<xsl:if test="((position() = last()) and
((position() mod $group-size) != 0))">
group <xsl:value-of
select="floor(position()
div $group-size) + 1" /><xsl:text> - </xsl:text>
<xsl:for-each select=". |
preceding-sibling::node[position() < $n]">
<xsl:value-of select="." /><xsl:if
test="position() !=
last()"><xsl:text>,</xsl:text></xsl:if>
</xsl:for-each>
<xsl:text>
</xsl:text>
</xsl:if>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
I invoke Xalan like this:
java org.apache.xalan.xslt.Process -in file.xml
-xsl
file.xsl -PARAM group-size 2
The output is fine for -PARAM group-size values of
1,2,3 & 4. But for -PARAM group-size values of 5
and
above, the ouput is not coming as expected. For
e.g.,
for -PARAM group-size 5, the output received is -
group 1 - a,s,d,f,g
group 2 - h,
I tested the same XSL with Saxon-SA 8.1.1 and
MSXSL
4,
and both produce correct result for all the cases.
Both Saxon and MSXSL produce the following output
for
group-size=5 -
group 1 - a,s,d,f,g
group 2 - h,j,k,l
Does this look like a Xalan bug?
Regards,
Mukul
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Geert(_dot_)Josten(_at_)Daidalos(_dot_)nl
IT-consultant at Daidalos BV, Zoetermeer (NL)
http://www.daidalos.nl/
tel:+31-(0)79-3316961
fax:+31-(0)79-3316464
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