You want
<xsl:if test="parent::definition">
Or better still, build this into the match pattern for the template:
<xsl:template match="definition/node">
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Rahil Qamar Yahoo [mailto:qamar_rahil(_at_)yahoo(_dot_)co(_dot_)uk]
Sent: 20 January 2005 12:01
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] accessing parent element in if clause
Hi
Im sure its a fairly basic question for most but Im just
starting out on
XSLT and cant find any resources to solve my problem.
I want to perform an operation based on an 'if' clause as shown below
-----------------------------------
<xsl:template match="/">
<PrimeConcept><xsl:apply-templates
select="/archetype/definition/node"/>
</PrimeConcept>
</xsl:template>
<xsl:template match="node">
<xsl:if test="parent::node()=definition">
<xsl:attribute name="id"><xsl:value-of
select="@id"/></xsl:attribute>
<xsl:attribute name="type"><xsl:value-of
select="@rm_class"/></xsl:attribute>
</xsl:if>
</xsl:template>
----------------------------------
Theres a problem with the <xsl:if> statement where Im trying to
determine whether the <node> element is the child of the <definition>
element. I think theres a problem in the way Im trying to access the
parent node but cant figure out the right way.
Could someone please help.
Thanks
Rahil
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