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Re: Understanding Identity Transformations

2005-02-13 11:30:23


   Tempore 14:47:08, die 02/13/2005 AD, hinc in  
   xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com scripsit David Carlisle 
<davidc(_at_)nag(_dot_)co(_dot_)uk>:

   > If A is a node set with two or more nodes that are not string-equal
   > then A != x is always true for any value of x.
   That's interesting... So you can use not(A!=B) to check if all nodes in  
   two node-sets A and B are stingwise identical; Now isn't this a good use  
   of '!=' ?


not(A!=B) is true just if A!=B is false which is only the case if every
node in A is equal to every node in B. If that's what you want to test
for then the expression is put to good use, but it's rather rare to have
a node set where all the nodes are string equal (unless it's something
like @abc where you know there is at most one node in the set).

David


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