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RE: Scope of xml source, includes, and inline xml

2005-03-31 13:53:13
The following xml document is our main document, which I still don't
have the terminology for.  It might look like:

<data>
  <foo>1</foo>
  <foo>3</foo>
  <foo>5</foo>
  <foo>2</foo>
  <foo>99</foo>
</data>

Lets say our XSLT creates a global variable "foo_test" and it imports
an external data source which looks like:

<foo_test>
  <foo>3</foo>
  <foo>99</foo>
</test_foo>

Will the following expression work:
<xsl:apply-templates select="data/foo = $foo_test//foo"/>

The expression (data/foo = $foo_test//foo) returns the boolean value true,
indicating that a match exists. xsl:apply-templates can only be applied to
nodes, not to booleans.

If you want to apply templates to all nodes in <data> that have a
counterpart in <foo_test>, you can use:

<xsl:apply-templates select="data/foo[. = $foo_test/foo_test/foo]"/>

Resulting in a match on:
foo = 3; and foo = 4

Where did you get foo = 4 from?


Now, let do the reverse of this and match on all $foot_test foo
elements so we have:
<xsl:apply-templates select="$foo_test//foo"  mode="my_external_foo"/>

And we have the template:
<xsl:template match="foo" mode="my_external_foo">
  <!-- AT THIS POINT.. 
        HOW DO WE REFER BACK TO MAIN XML SOURCE??? -->

Assign a global variable to the "main XML source" using
<xsl:variable name="root" select="/"/>


Michael Kay
http://www.saxonica.com/



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