I wish to add something important.. There is something
called "document order" - which is order of nodes in
the original document(and it is fixed). In
xsl:for-each the select attribute evaluates to a
node-set. The XSLT 1.0 spec says (about select
attribute of xsl:for-each).. "the nodes are processed
in document order, unless a sorting specification is
present"..
So the "select attribute" of for-each selects a
subtree with the original tree.. And this subtree
(i.e. the node-set) is processed in document order..
So you can expect in which order the output will
appear!
So it is sequential processing from "document order
point of view"..
Regards,
Mukul
--- Mukul Gandhi <mukul_gandhi(_at_)yahoo(_dot_)com> wrote:
if I can add a bit to what others have said..
When we specify some XPath expression in select
attribute of xsl:for-each (like Person/Age), we are
asking the XSLT processor to select a portion of
input
tree, and traverse all the nodes "on this subset" of
input tree. The nodes of this subtree (specified by
select attribute) may be scattered at various places
in the original source tree. The processor has to
traverse the nodes of this subtree. It may do so
using
any strategy like parallel, depth-first-search,
breadth-first-search or something similar..
So imagining sequential execution in xsl:for-each
loop
is not right..
Regards,
Mukul
--- Katharina Kreis <katharinakreis(_at_)web(_dot_)de> wrote:
Hi!
I need to exit my xsl:for-each tag when I'm
reaching
a value. Example:
<xsl:for-each select="Person/Age">
<xsl:if test=".='30'>
...
<!-- Here I need to exit xsl:for-each -->
</xsl:if>
</xsl:for-each>
...
In Java or C++ there exists a break or exit
keyword
to do this. How can
I do this with xsl?
Katharina
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