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RE: extracting data from html part result...

2005-05-12 07:32:16
Several permutations work...

<xsl:template match="div">
        <xsl:copy-of select="@id = 'announcements"/>
</xsl:template>

and...

<xsl:template match="html/body">
        <xsl:copy-of select="html/body/div[(_at_)id = 'announcements']"/>
</xsl:template>

...but I am only getting the text from the nodes, now ALL the html data
is stripped not just above and below the div

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Aaron Johnson
GUI / XSLT development
Academic Technologies Group [ATG]
University of the West of England
ext: 81051
t: 0117 3281051 
www: http://atg.uwe.ac.uk/aaron
e: aaron2(_dot_)johnson(_at_)uwe(_dot_)ac(_dot_)uk 

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-----Original Message-----
From: David Carlisle [mailto:davidc(_at_)nag(_dot_)co(_dot_)uk] 
Sent: 12 May 2005 14:55
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] extracting data from html part result...


  I only want the contents of the div to be extracted, and not the html
  elements above and below (head, body etc...)


<xsl:template match="/">
  <xsl:apply-templates select="/path/to/the/div/you/want"/>
</xsl:template>

  <xsl:template match="div[(_at_)id = 'announcements']">
          <xsl:apply-templates select="div[(_at_)id = 'announcements']"/>
  </xsl:template>

This will produce no output unless the div with id 'announcements' has a
child element also called div with the same id.

If all you want is a copy of one div with no actual transformation at
all then you don't need to use apply-templates at all, just



<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/">
  <xsl:copy-of select="/path/to/the/div/you/want"/>
</xsl:template>
</xsl:stylesheet>

is all you need.

David

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