The biggest difference with not() is that it will first check for existence the
node and might fail on that account - not because the values are different.
But I think you can do a simpler test for your needs - how about this:
<xsl:if test="count(row/x[. != 0]) > 0)">
<xsl:message>Error<xsl:message>
</xsl:if>
-----Original Message-----
From: Jaime Stuardo [mailto:jstuardo(_at_)security(_dot_)cl]
Sent: Wednesday, June 08, 2005 10:12 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] (correction) [xsl] differences between x != 0 and not(x = 0)
Sorry, this is what to accomplish:
1.
<row>
<x>0</x>
</row>
<row>
<x>4</x>
</row>
<row>
<x>0</x>
</row>
The test should return FALSE
2.
<row>
<x>0</x>
</row>
<row>
<x>0</x>
</row>
<row>
<x>0</x>
</row>
The test should return TRUE.
That is, when ALL nodes have value of 0, I have to do something, and when at
least one x has a value different from 0, I want to do other thing. I want to
use <xsl:if>, not <xsl:choose>
Thanks
Jaime
-----Mensaje original-----
De: Jaime Stuardo
Enviado el: Miércoles, 08 de Junio de 2005 10:03
Para: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Asunto: [xsl] differences between x != 0 and not(x = 0)
Hi all..
I always forgot this thing.
If I want to test that all nodes has value different from 0, I have to
use x!=0 or not(x=0) ?
For example,
<row>
<x>0</x>
</row>
<row>
<x>4</x>
</row>
<row>
<x>0</x>
</row>
The test for the above example should return TRUE.
<row>
<x>0</x>
</row>
<row>
<x>0</x>
</row>
<row>
<x>0</x>
</row>
The test for the above example should return FALSE.
Thanks
Jaime
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