Hi Chandu,
XSLT is a functional programming language and not a procedural one.
Hence, what you ask has to be handled differently. Your input xslt has to
have atleast as many nodes as the upper limit in the for loop (1000 in your
case) for this to work. Or in your case since you want the var reset for
every 100
nodes, 10 nodes atleast 100 deep I would imagine.
The general idea is outlined below: You would need something to call your
iterate template though.
<xsl:template name="iterate">
<xsl:for-each select="ancestor::node()[position() < 100]">
<xsl:call-template name="fun2">
<xsl:with-param name="var" select="0"/>
</xsl:call-template>
</xsl:for-each>
</xsl:template>
<xsl:template name="fun2">
<xsl:param name="var"/>
<!-- dom something with var here -->
<xsl:if test="$var = 100">
<xsl:call-template name="iterate">
</xsl:if>
<xsl:choose>
<xsl:when test="$var = 100">
<xsl:call-template name="iterate"/>
</xsl:when>
<xsl:otherwise>
<xsl:call-template name="fun2">
<xsl:with-param name="var" select="number($var)+1"/>
</xsl:call-template>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:for-each>
"ChandraShekar, A"
<ChandraShekar(_dot_)A(_at_)s To:
<xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
iemens.com> cc: (bcc:
omprakash.v/Polaris)
Subject: [xsl] Increment a
variable
08/18/2005 10:04
AM
Please respond to
xsl-list
Hello,
I don't know whether this question is stupid question or not?
How can I achieve following c++ code in XSLT.
void fun1()
{
for(int i=0;i<1000;i++)
{
fun2(i);
}
}
void fun2(int var)
{
if ( var == 0 )
{
var++;
// do something
}
else
{
Var++;
// do something
}
if ( var == 100 )
{
Var = 0;
// do something
}
}
Thanks in advance,
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