RE: Increment a variable

Chandrashekar, XSLT variables are not mutable, unlike those in most 
programming laguages -- this follows the thinking in functional languages 
not allowing side-effects.  Thus, doing something repeatedly is usually 
achieved (in XSL 1.0) via recursion.
In your case:

<xsl:template match="/">
   <xsl:call-template name="fun1">
       <xsl:with-param name="end" select="1000"/>
   </xsl:call-template>
</xsl:template>

<xsl:template name="fun1">
   <xsl:param name="end" select="0"/>
   <xsl:param name="start" select="0"/>

   <xsl:if test="$start &lt; $end">
       <xsl:call-template name="fun2"/>
       <xsl:call-template name="fun1">
           <xsl:with-param name="end" select="1000"/>
           <xsl:with-param name="start" select="$start + 1"/>
       </xsl:call-template>
   </xsl:if>
</xsl:template>

<xsl:template name="fun2">
 ...etc
</xsl:template>

--A

> From: "ChandraShekar, A" <ChandraShekar(_dot_)A(_at_)siemens(_dot_)com>
> Reply-To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
> To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
> Subject: [xsl] Increment a variable
> Date: Thu, 18 Aug 2005 10:04:39 +0530
>
>  Hello,
>         I don't know whether this question is stupid question or not?
>
>         How can I achieve following c++ code in XSLT.
>
>         void fun1()
>         {
>                 for(int i=0;i<1000;i++)
>                 {
>                    fun2(i);
>                 }
>         }
>
>         void fun2(int var)
>         {
>                 if ( var == 0 )
>                 {
>                         var++;
>                         // do something
>                 }
>                 else
>                 {
>                         Var++;
>                         // do something
>                 }
>                 if ( var == 100 )
>                 {
>                         Var = 0;
>                         // do something
>                 }
>         }
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