It's basically OK.
But your match="/" template is the same as the built-in template for
document nodes; and you only want the match="node()" template to handle
elements, so it would be better to say so by writing match="*".
You need to be aware that if your source document contains attributes such
as xml:space, xml:lang, or xsi:type, they will get mangled.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Joe Fawcett [mailto:joefawcett(_at_)hotmail(_dot_)com]
Sent: 02 October 2005 19:01
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Identity without namespaces
Dear All
I'm trying to write a transform that is basically an identity
transform but
without any namespaces being copied.
I know this is easier in version 2.0 but would anyone comment
on my effort
below, it seems to work but have I missed anything or could
it be simplified?
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="@*">
<xsl:attribute name="{local-name()}">
<xsl:value-of select="." />
</xsl:attribute>
</xsl:template>
<xsl:template match="comment() | processing-instruction() | text()">
<xsl:copy />
</xsl:template>
<xsl:template match="node()">
<xsl:element name="{local-name()}">
<xsl:apply-templates select="node()|@*"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
Thanks
Joe
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