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RE: Identity without namespaces

2005-10-02 13:10:29
It's basically OK.

But your match="/" template is the same as the built-in template for
document nodes; and you only want the match="node()" template to handle
elements, so it would be better to say so by writing match="*".

You need to be aware that if your source document contains attributes such
as xml:space, xml:lang, or xsi:type, they will get mangled. 

Michael Kay
http://www.saxonica.com/ 

-----Original Message-----
From: Joe Fawcett [mailto:joefawcett(_at_)hotmail(_dot_)com] 
Sent: 02 October 2005 19:01
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Identity without namespaces

Dear All

I'm trying to write a transform that is basically an identity 
transform but 
without any namespaces being copied.
I know this is easier in version 2.0 but would anyone comment 
on my effort 
below, it seems to work but have I missed anything or could 
it be simplified?

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

  <xsl:template match="/">
    <xsl:copy>
      <xsl:apply-templates select="node()|@*"/>
    </xsl:copy>
  </xsl:template>


  <xsl:template match="@*">
    <xsl:attribute name="{local-name()}">
      <xsl:value-of select="." />
    </xsl:attribute>
  </xsl:template>

  <xsl:template match="comment() | processing-instruction() | text()">
    <xsl:copy />
  </xsl:template>

  <xsl:template match="node()">
    <xsl:element name="{local-name()}">
      <xsl:apply-templates select="node()|@*"/>
    </xsl:element>
  </xsl:template>

</xsl:stylesheet>


Thanks

Joe 

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